Saturday, October 22, 2011

Aptitude Answers 1

Here are the answers to the last week's aptitude questions. Read more for the answers. Refer here for the corresponding questions!!!




1.Ans: (b)20:36:63

 Method:
             4*9/4:7*9/4
             5:9:63/4
             20:36:63

2.Ans: (a) 4*4/9 days (or) 40/9. days


Method:
           A--> 8days --> 1 day work=1/8
           B-->10days =1/10
            A+B = 1/8+1/10
                     = 9/40
             40/9 = 4*4/9 days.

3.Ans:8+8+8+88+888=1000


4.Ans: (c) Sunday

Method:
           28 may 2006 =2005 year + period from 1.1.2006 to 28.5.2006
           Odd days in 1600 year = 0
           Odd days in 400 year = 0
           5 year = (4 ordinary year + 1 leap year)
                      = (4*1+1*2)
                      = 6 odd days.
            Jan      feb      mar     apr     may
            31   +  28   +   31  +  30  +  28     = 148 days.
                    148 days = (21 weeks + 1 day)
                                   = 1 odd day.
Total Number of odd days = 0+0+6+1 =7
              Therefore there is no odd day. Hence it's Sunday. 


5.Ans: (d) 100%

 Method:
           C.P  be RS  *   and S.P  be  RS .Y
           3(y-x)  = 2y-x = y =2x
           Profit  =RS(y-x) =2x-x
                      =RS.x
          Profit%  =(x/x*100)% =100%


6.Ans:(b) 28

Method:
          n(n-1)/2 = number of  hand shakes.
                8(7)/2 = 28
7. Ans:
           (d) 2800

8.Ans:
        (b) M
Method:
E=5(alphabet)
M=13
H=8
(5+8=13)
Same method I=9
D=4
(9+4=13)
So ans is M

9. Ans:
               4/4+4*4=20
Method:
         4/4=1+4=5*4=20.
10. Ans:
           (a)  Cost price of horse = Rs. 400 & the cost price of cart = 200.
Method:-

Let x be the cost price of the horse and y be the cost price of the cart.
In the first sale there is no loss or profit. (i.e.) The loss obtained is equal to the
gain.
Therefore (10/100) * x = (20/100) * y
X = 2 * y -----------------(1)
In the second sale, he lost Rs. 10. (i.e.) The loss is greater than the profit by
Rs. 10.
Therefore (5 / 100) * x = (5 / 100) * y + 10 -------(2)
Substituting (1) in (2) we get
(10 / 100) * y = (5 / 100) * y + 10
(5 / 100) * y = 10
y = 200
From (1) 2 * 200 = x = 400.

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